Physics · Nuclear equationsHigherAmericium decays by Alpha emissionA95241X=96237X_{95}^{241}X = _{96}^{237}X95241X=96237X + particleB95241X=93237X_{95}^{241}X = _{93}^{237}X95241X=93237X + particleC95241X=96241X_{95}^{241}X = _{96}^{241}X95241X=96241X + particleD95241X=93241X_{95}^{241}X = _{93}^{241}X95241X=93241X + particleChoose an answer — or press 1234